Well, it's correct that this is a well-defined system, but for the second example the cycle-finding algorithm would output a third equation that would need to be discarded using whatever means available. For convenience here is the same picture again:Z1202 wrote:Why not? In the example ABCD we havestratum wrote:For the voltage law, the use absolute potentials rather than potential differences in the equations does not solve the redundancy problem

Va-Vb=Iab*R5

Vb-Vc=Ibc*R1

Vc-Vd=Icd*R4

Va-Vd=1V

Vd=0

Iab-Ibc=0

Ibc-Icd=0

Icd-Ida=0

Looks to me like a well-defined system.

Vda+Vab+Vbc+Vcd=0

Vdc+Vce+Vef+Vfd=0

Vda+Vab+Vbc+Vce+Vef+Vfd+Vda=0 (redundant)

If we rewrite these equations using absolute potentials, the third equation is still redundant.