Why would I hate you for at least trying to answer my thread's question? Your answer would be right if "linear" automation of the fader actually moved the fader linearly, but in Reaper a "linear" automation of the fader doesn't really do that, as it's easy to verify. So, you're wrong (i.e., you buggered up). In Reaper, applying a "linear" envelope to the fader really applies a linear envelope to the amplitude of the signal (not a linear envelope to the amplitude's log, as you assumed).xoxos wrote:your slider is already logarithmic because decibels, so a linear automation contour would produce an "exponential" amplitude decay. hehehehe. you can hate me, i'm right.
Why do you believe that?xoxos wrote:ftr, sj is right, but his criteria are above your scope of interest.
And why do you believe that? Another of your errors, like the one you made about Reaper's fader-automation?xoxos wrote:don't bash him, five years from now you'll know what he was talking about, and realise he is trying to inform you
Anyone who applies a linear fade in Reaper will hear what an actual linear decay sounds like.xoxos wrote:developers are the only people who will ever hear what an actual linear decay sounds like
yes, of course, butt-hurt Cubase fanboy in Alabama, you are way too smart for me to understand how awesome you are.SJ_Digriz wrote:lol, if they didn't understand my statement ... this one is going to soar over heads at 30k ft.xoxos wrote:btw you're all all of you buggered upyour slider is already logarithmic because decibels
