Reason vs. Cubase Blind Testing @ DOA

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FaX wrote:
kritikon wrote:
KVR: questioning the undeniable truth of 1+1=2

But 1+1=10 (in the binary world) :P
1+1 = 01 not 10 in binary :lol: .
01+01 is 10 ... should I get into the details?

Let A1, A2, B1 and B2 be the inputs to the adder, C, S1 and S2 are the outputs.

Code: Select all

A1  B1  S1  S1c
0   0   0   0
0   1   1   0
1   0   1   0
1   1   0   1

S1 = A1 xor B1
S1c = A1 and B1

A2  B2  S1c S2s S2  C
0   0   0   0   0   0
0   1   0   1   1   0
1   0   0   1   1   0
1   1   0   0   0   1
0   0   1   0   1   0
0   1   1   1   0   0
1   0   1   1   0   0
1   1   1   0   1   1

S2 = (A2 xor B2) xor S1c
C = (A2 and B2)

So, A1 = B1 = 1, A2 = B2 = 0
S1 = A1 xor B1 = 1 xor 1 = 0
S2 = (A2 xor B2) xor (A1 and B1)
   = (0 xor 0) xor (1 and 1)
   = 0 xor 1
   = 1

Thus, the result is 10. 

Post

arke wrote:
FaX wrote:
kritikon wrote:
KVR: questioning the undeniable truth of 1+1=2

But 1+1=10 (in the binary world) :P
1+1 = 01 not 10 in binary :lol: .
01+01 is 10 ... should I get into the details?

Let A1, A2, B1 and B2 be the inputs to the adder, C, S1 and S2 are the outputs.

Code: Select all

A1  B1  S1  S1c
0   0   0   0
0   1   1   0
1   0   1   0
1   1   0   1

S1 = A1 xor B1
S1c = A1 and B1

A2  B2  S1c S2s S2  C
0   0   0   0   0   0
0   1   0   1   1   0
1   0   0   1   1   0
1   1   0   0   0   1
0   0   1   0   1   0
0   1   1   1   0   0
1   0   1   1   0   0
1   1   1   0   1   1

S2 = (A2 xor B2) xor S1c
C = (A2 and B2)

So, A1 = B1 = 1, A2 = B2 = 0
S1 = A1 xor B1 = 1 xor 1 = 0
S2 = (A2 xor B2) xor (A1 and B1)
   = (0 xor 0) xor (1 and 1)
   = 0 xor 1
   = 1

Thus, the result is 10. 

The " :lol: " was in there for a Reason :hihi: .

Post

You can all just swivel on my 10th finger.


:P

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