Here is the code as provided by thierry rochebois, I translated and added a few comments.aciddose wrote:i have been unable to find the function to calculate the correct gain factor based upon frequency. the function most likely is more complex than the generator itself.

Code: Select all

```
/* clair.c Examen Partiel 2b
T.Rochebois
02/03/98
*/
#include <stdio.h>
#include <math.h>
main()
{
double phase=0,dphase,freq,compensation;
double aw0=0,aw1=0,ax0=0,ax1=0,ay0=0,ay1=0,az0=0,az1=0,sortie;
short aout;
int sr=44100; //sample rate (Hz)
double f_debut=55.0;//start freq (Hz)
double f_fin=sr/6.0;//end freq (Hz)
double octaves=log(f_fin/f_debut)/log(2.0);
double duree=50.0; //duration (s)
int i;
FILE* f;
f=fopen("saw.pcm","wb");
for(i=0;i<duree*sr;i++)
{
//exponential frequency sweep
//Can be replaced by anything you like.
freq=f_debut*pow(2.0,octaves*i/(duree*sr));
dphase=freq*(2.0/sr); //normalised phase increment
phase+=dphase; //phase incrementation
if(phase>1.0) phase-=2.0; //phase wrapping (-1,+1)
//polynomial calculation (extended continuity at -1 +1)
// 7 1 3 1 5
//P(x) = --- x - -- x + --- x
// 360 36 120
aw0=phase*(7.0/360.0 + phase*phase*(-1/36.0 + phase*phase*(1/120.0)));
// quad differentiation (first order high pass filters)
ax0=aw1-aw0; ay0=ax1-ax0; az0=ay1-ay0; sortie=az1-az0;
//compensation of the attenuation of the quad differentiator
//this can be calculated at "control rate" and linearly
//interpolated at sample rate.
compensation=1.0/(dphase*dphase*dphase*dphase);
// compensation and output
aout=(short)(15000.0*compensation*sortie);
fwrite(&aout,1,2,f);
//old memories of differentiators
aw1=aw0; ax1=ax0; ay1=ay0; az1=az0;
}
fclose(f);
}
```