AFAIK impulse invarinat transform is same as sampling impulse response which would result in aliased spectrum of discrete version compared to contionus.mystran wrote:You can have exactly the same frequency response up-to aliasing. That's impulse invariance transform. Should be straight-forward to prove that since sinc is infinite you can't have exactly the same frequency response as the band-limited version of the finite order ration transfer function H(s) except in degenerate special cases.
I don't know if I got you right for the other part, but if I want to match "relevant" parts of the spectrum (up to fs/2) than I would have to band limit H(s) and H*(z) as well (since H*(z)=H*(exp(jwT)) has infite spectrum as well, just that it's periodic).
Me too, I'm sorry that I brought it up (on second reading I figured out that authors cant even agree whether contionus time problem is stiff or numerical solution is stiff or something completly different)mystran wrote: The whole stiffness thing sucks as a concept. Honestly.
