Code: Select all
| D A/C# | D G/B | C |
Code: Select all
| D A/C# | D G/B | C |
jancivil wrote: Wed Jun 10, 2020 12:29 am The standard depiction of inversions figures the bass like so:
Root position is 5/3 (self-explanatory); 1st inversion is 6/3, eg., F A D, 3rd and 6th from bass F; 2nd inversion is 6/4, eg., G C E, 4th and 6th from bass G. Then we can figure chord of the seventh: 1st inversion is called the 6/5 chord, abbreviated from 6/5/3, eg., F A C D; 2nd inversion is called the 4/3 chord, abbreviated from 6/4/3, eg., G B C E; 3rd inversion is called 4/2 or the 2 chord, abbreviated from 6/4/2, eg., F G B D.
why isn't it abbreviated as 6/4?is there any particular rules to name inversions in certain order?2nd inversion is called the 4/3 chord, abbreviated from 6/4/3, eg., G B C E;
if I had written G E B C would it still be abbriviated as 4/3?jancivil wrote: Wed Jun 10, 2020 6:00 pm Because the triad in 2nd inversion is 6/4; the 3 in the 2nd inversion 7th chord, - eg., G B C E (C^7/G) - shows the 7th, ie., it’s the ‘business end’ of the figure.
Example:msf sadib wrote: Tue Jun 09, 2020 9:31 pm So in triads there's root position (1-3-5) 1st inversion (3-5-1) & 2nd inversion (5-1-3).But what if I arrange it like (5-3-1) or (1-5-3) or (3-1-5); what that be called voicing or something like that? Or maybe there's other naming system for that which I'm not aware of.Let me know!
I know it doesn't make sense.But it is possible to make that variation.so even if I write that 5-3-1.it would still be considered 2nd inversion anyway right?excuse me please wrote: Wed Jun 10, 2020 6:24 pmExample:msf sadib wrote: Tue Jun 09, 2020 9:31 pm So in triads there's root position (1-3-5) 1st inversion (3-5-1) & 2nd inversion (5-1-3).But what if I arrange it like (5-3-1) or (1-5-3) or (3-1-5); what that be called voicing or something like that? Or maybe there's other naming system for that which I'm not aware of.Let me know!
1-3-5=C1-E1-G1 basic
3-5-1=E1-G1-C2 inv 1
5-1-3=G1-C2-E2 inv 2
There are no more variations as it comes to their notation; logically 5-3-1 could mean G1-E1-C1 or G1-E1-C2 or G1-E2-C2, so it makes no sense etc.
The distance between the notes is addressed by only two inversions.
So you have a standard range between the notes, depending on the basic chord, which is in this case C1-E2. That's all there is to know afaiac.
But jan how do I know this? Suppose if it's written 4/3 how do I know if the E(in this example) is above or below provided that I'm not informed about the position of that Ejancivil wrote: Wed Jun 10, 2020 6:08 pm Yes. The 4 & the 3 are still the 4 & the 3 essentially. IE., the octave higher 4 (11, 18, ad infin) you don’t figure. Inessential to the meaning.
In these first inversion examples I'm thinking that they're written in traditional 3-5-1.but if it were something other like 3-1-5 would I still write A/C# or G/B or something other?BertKoor wrote: Wed Jun 10, 2020 5:21 pm I use the notation with slash for odd bass notes. Could only think of this example fragment from Queen - One Vision
Code: Select all
| D A/C# | D G/B | C |
All you need to understand is the chord is A, and the bass is C#.msf sadib wrote: Wed Jun 10, 2020 6:51 pmIn these first inversion examples I'm thinking that they're written in traditional 3-5-1.but if it were something other like 3-1-5 would I still write A/C# or G/B or something other?BertKoor wrote: Wed Jun 10, 2020 5:21 pm I use the notation with slash for odd bass notes. Could only think of this example fragment from Queen - One Vision
Code: Select all
| D A/C# | D G/B | C |
It figures the bass. Any numbers, therefore, are above the bass.msf sadib wrote: Wed Jun 10, 2020 6:47 pmBut jan how do I know this? Suppose if it's written 4/3 how do I know if the E(in this example) is above or below provided that I'm not informed about the position of that Ejancivil wrote: Wed Jun 10, 2020 6:08 pm Yes. The 4 & the 3 are still the 4 & the 3 essentially. IE., the octave higher 4 (11, 18, ad infin) you don’t figure. Inessential to the meaning.
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